This one does not get past Chapter 1 of any fluid mechanics textbook. It could be solved by anyone studying for 'O' Level (Matriculation) Physics and certainly does not require expert advice on a bulk handing forum.■

Originally Posted by Mountain

Please kindly some one, an expert, to answer this question:

A water pump piston of cross sectional area of 0.875 square metres under 280.00 kg THRUST can go down for 0.32 metres.

The pump fills a volume of 0.875 x 0.32 = 0.280 cubic metre after moving for 0.32 metres. This volume of 0.280 cubic metre contains 280.00kg of water. Now how HIGH this pump can expel the water through a pipe of 10.00 sqr cm cross sectional area?

Since this puzzle has no more clues:

The speed of the piston is not specified; the length of the 10 square centimeter pipe is not specified; The pump is not specified as being a reciprocating or linear piston with a piston rod. one must only assume the volume moved is only the volume in the piston at bottom center to top dead center of the stroke but that is also an unknown as the length of the 10. 00 square centimeter pipe is also an issue as is the number of pipe reduction fittings used is unkown; the size of the reducing fitings is unknown, the resistance of the fittings, the water temperature; the rate of evaporation; the altitude of the experiment and its effect on the surface area water pressure in the cylinder; the amount of bypass in the piston if any; the amount of energy it takes to push the cylinder to top dead center; the amount of vacuum created behind the piston assuming it is dry behind the piston.

The only plausible amount is the 280. 00 kilogram amount less the amount left in the pipe fitting of unknown distance in length..

If you really want understand water movement you should google the weighlock building at the Erie Canal Museum.

I did not mean to ruin the fun of the problem

lzaharis ■