Belt Speed and Belt Tension ?

Posted in: , on 10. Aug. 2009 - 13:10

Dear All,

In the Page 56 of CEMA book, it is mentioned that:

"An increase in belt speed permits decreases in belt width and belt tension"

Can you please explain to me the relationship between belt speed and belt tension? why the belt tension decreases when the speed increases?

Thank you in advance.

Best Regards, [I][B]Alex Kaveh Senior Mechanical Engineer Mobile : 0451 563 155 Email : [email]alexkaveh@gmail.com[/email][/B][/I]

Re: Belt Speed And Belt Tension ?

Posted on 10. Aug. 2009 - 11:37

Dear Alex,

This can be deducted with the capacity = constant.

Capacity = Cross section * speed * density

Load = Cross section * Length

Belt tension = Load * friction factor

Cross section = Capacity / (speed * density)

Conclusion:

Higher speed results in smaller cross section (and smaller belt width) at equal capacity

Load = Capacity / (speed * density) * Length

Belt tension = = Capacity / (speed * density) * Length * friction factor

Conclusion:

Higher speed results in lower belt tension at equal capacity.

Evaluating the equations always explain how it works.

Have a nice day

Teus

Teus

Re: Belt Speed And Belt Tension ?

Posted on 10. Aug. 2009 - 08:56

Tension reduction approximately follows speed increase. Two points alter this assumption:

1. The counterweight value is torque (drive slip), belt sag, and dynamic control related. The counterweight reduction may not be reduced according to the increase in speed or visa-versa.

2. Speed, by itself, can be thought of as a temperature dependent property : increase in speed means an increase in rubber's rolling resistance similar to a decrease in temperature. Not 1:1, but at higher speed, it is significant with viscoelastic losses in belt cover in contact with idlers and in idler bearing lubricant.

Lawrence Nordell Conveyor Dynamics, Inc. website, email & phone contacts: www.conveyor-dynamics.com nordell@conveyor-dynamics.com phone: USA 360-671-2200 fax: USA 360-671-8450

Thank You

Posted on 12. Aug. 2009 - 12:44

Hi Nordell and Teus,

Thank you for your valuable replies.

Best Regards, [I][B]Alex Kaveh Senior Mechanical Engineer Mobile : 0451 563 155 Email : [email]alexkaveh@gmail.com[/email][/B][/I]