Dear rajendra.patel,

Firstly some questions.

1) What is the present compressor size in m3/min and bar?

2) What is the diameter of the conveying pipe(s)?

3) Do you intend to make 3 separate loading pipes or 1 loading pipe with 3 connection points?

1200m3/hr (20 m3/min) seems a lot of air for 24 m of pipeline with an ordinary bulktruck

Awaiting your information

best regards

teus ■

Dear Rajendra,

I made a pneumatic fly ash conveying calculation for:

horizontal distance 7 m

vertical distance 16 m

diameter pipeline 100 mm (4”)

compressor 15 m3/min = 0.25 m3/sec at 1 bar

calculated capacity = 27 tons/hr

air velocity begin of pipeline = 22 m/sec

air velocity end of pipeline = 40 m/sec

Then I made the same calculation for a 6”pipeline (0.145 m)

horizontal distance 7 m

vertical distance 16 m

diameter pipeline 145 mm (6”)

compressor 15 m3/min = 0.25 m3/sec at 1 bar

calculated capacity = 57 tons/hr

air velocity begin of pipeline = 10.3 m/sec

air velocity end of pipeline = 19.5 m/sec

Increasing the compressor from 15 m3/min to 20 m3/min at a 100 mm pipeline is the wrong way to go.

For a silo height of 24 m, the calculated capacity = 49 tons/hr

success

teus ■

Dear rajendra,

Calculation for a 6”pipeline (0.145 m)

horizontal distance 7 m

vertical distance 24 m

diameter pipeline 145 mm (6”)

compressor 15 m3/min = 0.25 m3/sec

Forum raj d 05-26-2008

Pressure discharge Fly-ash

Convey length = 31 m

Nu of bends= 3

Pump vol = .25 + .25 m^3/s

q-convey = 0.28 m^3/s

Dia begin = 145 mm ------Dia end = 145 mm

Kettle volume = 40.0 m^3

Fly-as vol.= 30.0 m^3

C-Vessel = 500 tons/hr

Kettle Fly-as content = 29.1 tons

Pipevolume = .51 m^3

----------Pipeline------------Syst. /Nr of .

Press----Cap-------mu-----Cap. /kettles---- v-begin-----v-end-----kWh/ton-----res.time

2.500----80--------78--------67 / 2.3---------5.7--------18.4----------0.72----------4.42

2.250----75--------73.-------64 / 2.1 --------6.1 --------18.5--------- 0.70--------- 4.19

2.000----71--------68.-------60 / 2.0 ---------6.6 -------18.6-------- 0.68 ----------3.95

1.750----66--------62.------ 57 / 1.9 ---------7.2--------18.8 -------- 0.66----------3.69

1.500----61--------56.------ 53 / 1.8 --------8.0---------18.9 ---------0.63--------- 3.42

1.250----55--------50.------ 48 / 1.6 --------8.9---------19.1----------0.61----------3.14

1.000----49--------44.------ 43 / 1.4 -------10.1---------19.3---------0.59 ----------2.85

0.750----42--------37.-------38 / 1.3--------11.7 -------19.5---------0.58 ---------- 2.54

0.500----33--------28. ------30 / 1.0---------13.9-------19.7----------0.59 ----------2.24

Empty pipeline pressure ...= 372.9 mmWC

Maximum system capacity : 67 t/hr 2.5 bar(o)

This calculation is for one separate system

3 separate system can operate in parallel.

One header with 3 feeders will result in a system that operates with different airflows from time to time and the parallel operating bulk trucks will interfere with each other.

For 3 compressors of 15 m3/min a filter of 90 m2 with a fan of 180m3/min is required, together with a silo safety valve.

Check the maximum allowable pressure of the bulk truck tanks.

Before you start building consult suppliers and/or designers.

success

teus ■

Dear rajendra,

What are the limitations of the bulker?

Is the design pressure is above 1.5 bar?

Is the bulk truck outlet big enough for a capacity of more than 50 tons/hr?

take care

teus ■

Dear rajendra,

If the compressor can deliver more than 1.5 bar, there is no reason not to operate at a higher pressure.

When unloading fly ash with your system, you can set the unloading pressure f.i. at 2.25 bar (by controlling the by pass air).

The capacity will increase accordingly.

The bulk truck outlet should preferably also be 6”

We are talking about 3 separate 6”pipelines and 3 separate compressors, not connected to each other.

Also keep in mind that the calculated flyash might be different in flow behaviour from toue actual fly ash.

best regards

teus ■